2x/x-3+4/x+3=24/9-x^2

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Solution for 2x/x-3+4/x+3=24/9-x^2 equation: 



2x/x-3+4/x+3=24/9-x^2

We move all terms to the left:

2x/x-3+4/x+3-(24/9-x^2)=0



Domain of the equation: 9-x^2)!=0

We move all terms containing x to the left, all other terms to the right

-x^2)!=-9

x!=-9/1

x!=-9

x∈R





Domain of the equation: x!=0

x∈R



We add all the numbers together, and all the variables

-(24/9-x^2)+2x/x+4/x=0

We get rid of parentheses

x^2+2x/x+4/x-24/9=0

We calculate fractions


x^2+(2x+36)/9x+(-24x)/9x=0

We multiply all the terms by the denominator


x^2*9x+(2x+36)+(-24x)=0

Wy multiply elements

9x^3+(2x+36)+(-24x)=0

We get rid of parentheses

9x^3+2x-24x+36=0

We do not support expression: x^3

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